The bond dissociation energy of H2 is 435 kJ mol1 (104 kcal mol1 ); that is, it takes this amount of energy to dissociate H2 into its atoms. Estimate the bond dissociation energy of H2 + and explain your answer.
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Reference Electrode There is no way to measure reduction potential of an isolated half reaction Only the difference is potential between 2 half cells can be added In order to assign E nought red to half reactions, reference electrode chosen, where the cell potential = 0.0 V Standard H Electrode 2H++2e>H2 EH+=0.0 V reversible not at equilibrium can be oxidation or reduction Example 5: Galvanic Cell Zn/Zn2+ Zn>Zn2++2e anode 2H++2e_>H2 cathoden+2H+>Zn2++H2 Ecell= ErEo or Ecell= EcEa 0.76=0VEZn2+=0.76 EZn2+ Ered table 20.1 in the book -oxidized+e→ reduced ions elements or compounds Top to bottom down E nought red low value Ered<0, easily oxidized Value Ered=less likely to undergo reduction Sign Ered att
Textbook: Organic Chemistry
Author: Marc Loudon, Jim Parise
This full solution covers the following key subjects: . This expansive textbook survival guide covers 239 chapters, and 1693 solutions. The full step-by-step solution to problem: 1.18 from chapter: 1.8 was answered by , our top Chemistry solution expert on 03/16/18, 03:35PM. This textbook survival guide was created for the textbook: Organic Chemistry, edition: 6. Organic Chemistry was written by and is associated to the ISBN: 9781936221349. The answer to “The bond dissociation energy of H2 is 435 kJ mol1 (104 kcal mol1 ); that is, it takes this amount of energy to dissociate H2 into its atoms. Estimate the bond dissociation energy of H2 + and explain your answer.” is broken down into a number of easy to follow steps, and 40 words. Since the solution to 1.18 from 1.8 chapter was answered, more than 211 students have viewed the full step-by-step answer.