Three arrows are shot horizontally. They have left the bow and are traveling parallel to the ground as shown in Figure Q4.4 . Air resistance is negligible. Rank in order, from largest to smallest, the magnitudes of the horizontal forces acting on the arrows. Some may be equal. State your reasoning.

Step 1 of 3 Step 2of 3 Let t=1 sec time taken by the bow to exert force on each arrow We know that F = ma 1 F=m(v/t) Horizontal force acting on the first arrow is1F =m(v/t) m=80g=80× 10 kg3 v=10 m/s t=1 sec F = 1 F 1m(v/t) 3 =80× 10 kg(10/1) =0.80 N Horizontal force acting on the second arrow is,2 =m(v/t) m=80g=80× 10 kg3 v=19 m/s t=1 sec F 2 F 2m(v/t) 3 =80× 10 (9/1) =0.72 N Horizontal force acting on the first arrow is3F =m(v/t) 3 m=90g=90× 10 kg v=9 m/s t=1 sec F 3 F 3m(v/t) 3 =90× 10 kg(9/1) =0.81 N