Precalculus: Graphical, Numerical, Algebraic 8th Edition solutions

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 14, expand the product. \((3x - 4)^2\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 14, expand the product. \((2x + 3)^2\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 14, expand the product. (2x + 1) (3x - 5)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 14, expand the product. (3y - 1) (5y + 4)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 58, factor completely. \(25x^2 - 20x + 4\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 58, factor completely. \(15x^3 - 22x^2 + 8x\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 58, factor completely. \(3x^2 + x^2 - 15x - 5\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 58, factor completely. \(y^4 - 13y^2 + 36\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 9 and 10, combine the fractions and reduce the resulting fraction to lowest terms. \(\frac{x}{2 x+1}-\frac{2}{x+3}\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 9 and 10, combine the fractions and reduce the resulting fraction to lowest terms. \(\frac{x+1}{x^{2}-5 x+6}-\frac{3 x+11}{x^{2}-x-6}\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 16, solve the equation graphically by finding x-intercepts. Confirm by using factoring to solve the equation. \(x^2 - x - 20 = 0\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 16, solve the equation graphically by finding x-intercepts. Confirm by using factoring to solve the equation. \(2x^2 + 5x - 3 = 0\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 16, solve the equation graphically by finding x-intercepts. Confirm by using factoring to solve the equation. \(4x^2 - 8x + 3 = 0\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 16, solve the equation graphically by finding x-intercepts. Confirm by using factoring to solve the equation. \(x^2 - 8x = -15\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 16, solve the equation graphically by finding x-intercepts. Confirm by using factoring to solve the equation. x(3x - 7) = 6

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 16, solve the equation graphically by finding x-intercepts. Confirm by using factoring to solve the equation. x(3x + 11) = 20

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 712, solve the equation by extracting square roots. \(4x^2 = 25\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 712, solve the equation by extracting square roots. \(2(x - 5)^2 = 17\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 712, solve the equation by extracting square roots. \(3(x + 4)^2 = 8\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 712, solve the equation by extracting square roots. \(4(u + 1)^2 = 18\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 712, solve the equation by extracting square roots. \(2y^2 - 8 = 6 - 2y^2\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 712, solve the equation by extracting square roots. \((2x + 3)^2 = 169\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 1318, solve the equation by completing the square. \(x^2 + 6x = 7\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 1318, solve the equation by completing the square. \(x^2 + 5x - 9 = 0\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 1318, solve the equation by completing the square. \(x^2 - 7x + \frac{5}{4} = 0\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 1318, solve the equation by completing the square. \(4 - 6x = x^2\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 1318, solve the equation by completing the square. \(2x^2 - 7x + 9 = 0 (x - 3) (x + 1) + 3x\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 1318, solve the equation by completing the square. \(3x^2 - 6x - 7 = x^2 + 3x - x(x + 1) + 3\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 1924, solve the equation using the quadratic formula. \(x^2 + 8x - 2 = 0\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 1924, solve the equation using the quadratic formula. \(2x^2 - 3x + 1 = 0\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 1924, solve the equation using the quadratic formula. \(3x + 4 = x^2\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 1924, solve the equation using the quadratic formula. \(x^2 - 5 = \sqrt{3x}\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 1924, solve the equation using the quadratic formula. x(x + 5) = 12

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 1924, solve the equation using the quadratic formula. \(x^2 - 2x + 6 = 2x^2 - 6x - 26\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 2528, estimate any x- and y-intercepts that are shown in the graph.

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 2528, estimate any x- and y-intercepts that are shown in the graph.

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 2528, estimate any x- and y-intercepts that are shown in the graph.

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 2528, estimate any x- and y-intercepts that are shown in the graph.

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 2934, solve the equation graphically by finding x-intercepts. \(x^2 + x - 1 = 0\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 2934, solve the equation graphically by finding x-intercepts. \(4x^2 + 20x + 23 = 0\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 2934, solve the equation graphically by finding x-intercepts. \(x^3 + x^2 + 2x - 3 = 0\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 2934, solve the equation graphically by finding x-intercepts. \(x^3 - 4x + 2 = 0\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 2934, solve the equation graphically by finding x-intercepts. \(x^2 + 4 = 4x\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 2934, solve the equation graphically by finding x-intercepts. \(x^2 + 2x = -2\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 35 and 36, the table permits you to estimate a zero of an expression. State the expression and give the zero as accurately as can be read from the table.

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 35 and 36, the table permits you to estimate a zero of an expression. State the expression and give the zero as accurately as can be read from the table.

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 37 and 38, use tables to find the indicated number of solutions of the equation accurate to two decimal places. Two solutions of \(x^2 - x - 1 = 0\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 37 and 38, use tables to find the indicated number of solutions of the equation accurate to two decimal places. One solution of \(-x^3 + x + 1 = 0\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 3944, solve the equation graphically by finding intersections. Confirm your answer algebraically. |t - 8| = 2

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 3944, solve the equation graphically by finding intersections. Confirm your answer algebraically. |x + 1| = 4

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 3944, solve the equation graphically by finding intersections. Confirm your answer algebraically. |2x + 5| = 7

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 3944, solve the equation graphically by finding intersections. Confirm your answer algebraically. |3 - 5x| = 4

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 3944, solve the equation graphically by finding intersections. Confirm your answer algebraically. \(|2x - 3| = x^2\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 3944, solve the equation graphically by finding intersections. Confirm your answer algebraically. |x + 1| = 2x - 3

Precalculus: Graphical, Numerical, Algebraic 8th Edition
Interpreting Graphs The graphs in the two viewing windows shown here can be used to solve the equation \(3\sqrt{x + 4} = x^2 - 1\) graphically. (a) The viewing window in (a) illustrates the intersection method for solving. Identify the two equations that are graphed. (b) The viewin

Precalculus: Graphical, Numerical, Algebraic 8th Edition
Writing to Learn Revisiting Example 6 Explain why all real numbers x that satisfy 1.324 < x < 1.325 round to 1.32.

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 4756, use a method of your choice to solve the equation. \(x^2 + x - 2 = 0\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 4756, use a method of your choice to solve the equation. \(x^2 - 3x = 12 - 3(x - 2)\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 4756, use a method of your choice to solve the equation. |2x - 1| = 5

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 4756, use a method of your choice to solve the equation. \(x + 2 - 2\sqrt{x + 3} = 0\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 4756, use a method of your choice to solve the equation. \(x^3 + 4x^2 - 3x - 2 = 0\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 4756, use a method of your choice to solve the equation. \(x^3 - 4x + 2 = 0\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 4756, use a method of your choice to solve the equation. \(|x^2 + 4x - 1| = 7\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 4756, use a method of your choice to solve the equation. \(|x + 5| = |x - 3|\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 4756, use a method of your choice to solve the equation. \(|0.5x + 3| = x^2 - 4\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 4756, use a method of your choice to solve the equation. \(\sqrt{x + 7} = -x^2 + 5\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
Group Activity Discriminant of a Quadratic The radicand \(b^2 - 4ac\) in the quadratic formula is called the discriminant of the quadratic polynomial \(ax^2 + bx + c\) because it can be used to describe the nature of its zeros. (a) Writing to Learn If \(b^2 - 4ac\ >\ 0\), what can you say a

Precalculus: Graphical, Numerical, Algebraic 8th Edition
Group Activity Discriminant of a Quadratic Use the information learned in Exercise 57 to create a quadratic polynomial with the following numbers of real zeros. Support your answers graphically. (a) Two real zeros (b) Exactly one real zero (c) No real zeros

Precalculus: Graphical, Numerical, Algebraic 8th Edition
Size of a Soccer Field Several of the World Cup 94 soccer matches were played in Stanford Universitys stadium in Menlo Park, California. The field is 30 yd longer than it is wide, and the area of the field is \(8800\ yd^2\). What are the dimensions of this soccer field?

Precalculus: Graphical, Numerical, Algebraic 8th Edition
Height of a Ladder Johns paint crew knows from experience that its 18-ft ladder is particularly stable when the distance from the ground to the top of the ladder is 5 ft more than the distance from the building to the base of the ladder as shown in the figure. In this position, how far up the bui

Precalculus: Graphical, Numerical, Algebraic 8th Edition
Finding the Dimensions of a Norman Window A Norman window has the shape of a square with a semicircle mounted on it. Find the width of the window if the total area of the square and the semicircle is to be \(200\ ft^2\).

Precalculus: Graphical, Numerical, Algebraic 8th Edition
True or False If 2 is an x-intercept of the graph of \(y=a x^{2}+b x+c\), then 2 is a solution of the equation \(a x^{2}+b x+c=0\). Justify your answer.

Precalculus: Graphical, Numerical, Algebraic 8th Edition
True or False If \(2 x^{2}=18\), then x must be equal to 3. Justify your answer.

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 6467, you may use a graphing calculator to solve these problems. Multiple Choice Which of the following are the solutions of the equation x(x - 3) = 0? (A) Only x = 3 (B) Only x = -3 (C) x = 0 and x = -3 (D) x = 0 and x = 3 (E) There are n

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 6467, you may use a graphing calculator to solve these problems. Multiple Choice Which of the following replacements for ? make \(x^{2}-5 x+?\) a perfect square? (A) \(-\frac{5}{2}\) (B) \(\left(-\frac{5}{2}\right)^{2}\) (C) \((-5)^{2}\)

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 6467, you may use a graphing calculator to solve these problems. Multiple Choice Which of the following are the solutions of the equation \(2 x^{2}-3 x-1-0\)? (A) \(\frac{3}{4} \pm \sqrt{17}\) (B) \(\frac{3 \pm \sqrt{17}}{4}\) (C) \(\frac{3 \pm \sqrt{

Precalculus: Graphical, Numerical, Algebraic 8th Edition
In Exercises 6467, you may use a graphing calculator to solve these problems. Multiple Choice Which of the following are the solutions of the equation |x - 1| = -3? (A) Only x = 4 (B) Only x = -2 (C) Only x = 2 (D) x = 4 and x = -2 (E) Ther

Precalculus: Graphical, Numerical, Algebraic 8th Edition
Deriving the Quadratic Formula Follow these steps to use completing the square to solve \(a x^{2}+b x+c=0\), \(a \neq 0\). (a) Subtract c from both sides of the original equation and divide both sides of the resulting equation by a to obtain \(x^{2}+\frac{b}{a} x=-\frac{c}{a}\) (b) Ad

Precalculus: Graphical, Numerical, Algebraic 8th Edition
Finding Number of Solutions Consider the equation \(\left|x^{2}-4\right|=c\). (a) Find a value of c for which this equation has four solutions. (There are many such values.) (b) Find a value of c for which this equation has three solutions. (There is only one such value.) (c) Find a v

Precalculus: Graphical, Numerical, Algebraic 8th Edition
Sums and Products of Solutions of \(a x^{2}+b x+c=0, a \neq 0\) Suppose that \(b^{2}-4 a c>0\). (a) Show that the sum of the two solutions of this equation is -(b/a). (b) Show that the product of the two solutions of this equation is c/a.

Precalculus: Graphical, Numerical, Algebraic 8th Edition
Exercise 70 Continued The equation \(2 x^{2}+b x+c=0\) has two solutions \(x_{1}\) and \(x_{2}\). If \(x_{1}+x_{2}=5\) and \(x_{1} \cdot x_{2}=3\), find the two solutions.