 3.1.1: In each of 1 through 8, find the general solution of the given diff...
 3.1.2: In each of 1 through 8, find the general solution of the given diff...
 3.1.3: In each of 1 through 8, find the general solution of the given diff...
 3.1.4: In each of 1 through 8, find the general solution of the given diff...
 3.1.5: In each of 1 through 8, find the general solution of the given diff...
 3.1.6: In each of 1 through 8, find the general solution of the given diff...
 3.1.7: In each of 1 through 8, find the general solution of the given diff...
 3.1.8: In each of 1 through 8, find the general solution of the given diff...
 3.1.9: In each of 9 through 16, find the solution of the given initial val...
 3.1.10: In each of 9 through 16, find the solution of the given initial val...
 3.1.11: In each of 9 through 16, find the solution of the given initial val...
 3.1.12: In each of 9 through 16, find the solution of the given initial val...
 3.1.13: In each of 9 through 16, find the solution of the given initial val...
 3.1.14: In each of 9 through 16, find the solution of the given initial val...
 3.1.15: In each of 9 through 16, find the solution of the given initial val...
 3.1.16: In each of 9 through 16, find the solution of the given initial val...
 3.1.17: Find a differential equation whose general solution is y = c1e2t + ...
 3.1.18: Find a differential equation whose general solution is y = c1et/2 +...
 3.1.19: . Find the solution of the initial value problem y y = 0, y(0) = 5 ...
 3.1.20: Find the solution of the initial value problem 2y 3y + y = 0, y(0) ...
 3.1.21: Solve the initial value problem y y 2y = 0, y(0) = , y (0) = 2. The...
 3.1.22: Solve the initial value problem 4y y = 0, y(0) = 2, y (0) = . Then ...
 3.1.23: In each of 23 and 24, determine the values of , if any, for which a...
 3.1.24: In each of 23 and 24, determine the values of , if any, for which a...
 3.1.25: Consider the initial value problem 2y + 3y 2y = 0, y(0) = 1, y (0) ...
 3.1.26: Consider the initial value problem (see Example 5) y + 5y + 6y = 0,...
 3.1.27: Consider the equation ay + by + cy = d, where a, b, c, and d are co...
 3.1.28: Consider the equation ay + by + cy = 0, where a, b, and c are const...
Solutions for Chapter 3.1: Homogeneous Equations with Constant Coefficients
Full solutions for Elementary Differential Equations and Boundary Value Problems  10th Edition
ISBN: 9780470458310
Solutions for Chapter 3.1: Homogeneous Equations with Constant Coefficients
Get Full SolutionsChapter 3.1: Homogeneous Equations with Constant Coefficients includes 28 full stepbystep solutions. This textbook survival guide was created for the textbook: Elementary Differential Equations and Boundary Value Problems, edition: 10. Since 28 problems in chapter 3.1: Homogeneous Equations with Constant Coefficients have been answered, more than 16819 students have viewed full stepbystep solutions from this chapter. This expansive textbook survival guide covers the following chapters and their solutions. Elementary Differential Equations and Boundary Value Problems was written by and is associated to the ISBN: 9780470458310.

CayleyHamilton Theorem.
peA) = det(A  AI) has peA) = zero matrix.

Conjugate Gradient Method.
A sequence of steps (end of Chapter 9) to solve positive definite Ax = b by minimizing !x T Ax  x Tb over growing Krylov subspaces.

Cross product u xv in R3:
Vector perpendicular to u and v, length Ilullllvlll sin el = area of parallelogram, u x v = "determinant" of [i j k; UI U2 U3; VI V2 V3].

Echelon matrix U.
The first nonzero entry (the pivot) in each row comes in a later column than the pivot in the previous row. All zero rows come last.

Elimination matrix = Elementary matrix Eij.
The identity matrix with an extra eij in the i, j entry (i # j). Then Eij A subtracts eij times row j of A from row i.

Ellipse (or ellipsoid) x T Ax = 1.
A must be positive definite; the axes of the ellipse are eigenvectors of A, with lengths 1/.JI. (For IIx II = 1 the vectors y = Ax lie on the ellipse IIA1 yll2 = Y T(AAT)1 Y = 1 displayed by eigshow; axis lengths ad

Four Fundamental Subspaces C (A), N (A), C (AT), N (AT).
Use AT for complex A.

Identity matrix I (or In).
Diagonal entries = 1, offdiagonal entries = 0.

Linear transformation T.
Each vector V in the input space transforms to T (v) in the output space, and linearity requires T(cv + dw) = c T(v) + d T(w). Examples: Matrix multiplication A v, differentiation and integration in function space.

Normal matrix.
If N NT = NT N, then N has orthonormal (complex) eigenvectors.

Orthogonal matrix Q.
Square matrix with orthonormal columns, so QT = Ql. Preserves length and angles, IIQxll = IIxll and (QX)T(Qy) = xTy. AlllAI = 1, with orthogonal eigenvectors. Examples: Rotation, reflection, permutation.

Orthonormal vectors q 1 , ... , q n·
Dot products are q T q j = 0 if i =1= j and q T q i = 1. The matrix Q with these orthonormal columns has Q T Q = I. If m = n then Q T = Q 1 and q 1 ' ... , q n is an orthonormal basis for Rn : every v = L (v T q j )q j •

Particular solution x p.
Any solution to Ax = b; often x p has free variables = o.

Permutation matrix P.
There are n! orders of 1, ... , n. The n! P 's have the rows of I in those orders. P A puts the rows of A in the same order. P is even or odd (det P = 1 or 1) based on the number of row exchanges to reach I.

Rotation matrix
R = [~ CS ] rotates the plane by () and R 1 = RT rotates back by (). Eigenvalues are eiO and eiO , eigenvectors are (1, ±i). c, s = cos (), sin ().

Semidefinite matrix A.
(Positive) semidefinite: all x T Ax > 0, all A > 0; A = any RT R.

Special solutions to As = O.
One free variable is Si = 1, other free variables = o.

Trace of A
= sum of diagonal entries = sum of eigenvalues of A. Tr AB = Tr BA.

Transpose matrix AT.
Entries AL = Ajj. AT is n by In, AT A is square, symmetric, positive semidefinite. The transposes of AB and AI are BT AT and (AT)I.

Wavelets Wjk(t).
Stretch and shift the time axis to create Wjk(t) = woo(2j t  k).