- 9-2.1: selling Find the rate of markup based on the selling price. Cost = ...
- 9-2.2: Markup markup rate of 60%based on the selling price. a. Find the se...
- 9-2.3: Selling Find the rate of markup based on the selling price. price =...
- 9-2.4: markup rate is 42% of the selling price. a. Find the selling price....
- 9-2.5: Markup rate based on selling markup = $250. Find the selling price....
- 9-2.6: Find the selling price for an item that costs $792 and is marked up...
- 9-2.7: An item is marked up $12. The markup rate based on selling price is...
- 9-2.8: Selling price $1.98; markup is 48% of the selling price. a. What is...
- 9-2.9: An item sells for $5,980 and costs $3,420. What is the rate of mark...
- 9-2.10: The selling price of an item is $18.50 and the markup rate is 86% o...
- 9-2.11: An item has a 30% markup based on selling price. The markup is $100...
- 9-2.12: An item costs $20 and sells for $50. a. Find the rate of markup bas...
- 9-2.13: An item has a 60% markup based on selling price. What is the equiva...
- 9-2.14: A 40% markup based on cost is equivalent to what percent based on s...
- 9-2.15: An air compressor costs $350 and sells for $695. Find the rate of m...
- 9-2.16: A lateral file is marked up $140, which represents a 28% markup bas...
- 9-2.17: A lawn tractor that costs the retailer $599 is marked up 36% of the...
- 9-2.18: A recliner chair that sells for $1,499 is marked up 60% of the sell...
- 9-2.19: Lowes plans to sell its best-quality floor tiles for $15 each. This...
- 9-2.20: A serving tray costs $1,400 and sells for $2,015. a. Find the rate ...
- 9-2.21: What is the equivalent markup based on cost of a water fountain tha...
- 9-2.22: A box of Acco paper clips is marked up 46% based on cost. What is t...
Solutions for Chapter 9-2: MARKUP BASED ON SELLING PRICE AND MARKUP COMPARISONS
Full solutions for Business Math, | 9th Edition
peA) = det(A - AI) has peA) = zero matrix.
Commuting matrices AB = BA.
If diagonalizable, they share n eigenvectors.
z = a - ib for any complex number z = a + ib. Then zz = Iz12.
A = S-1 AS. A = eigenvalue matrix and S = eigenvector matrix of A. A must have n independent eigenvectors to make S invertible. All Ak = SA k S-I.
Echelon matrix U.
The first nonzero entry (the pivot) in each row comes in a later column than the pivot in the previous row. All zero rows come last.
Exponential eAt = I + At + (At)2 12! + ...
has derivative AeAt; eAt u(O) solves u' = Au.
Invert A by row operations on [A I] to reach [I A-I].
Hermitian matrix A H = AT = A.
Complex analog a j i = aU of a symmetric matrix.
Incidence matrix of a directed graph.
The m by n edge-node incidence matrix has a row for each edge (node i to node j), with entries -1 and 1 in columns i and j .
Independent vectors VI, .. " vk.
No combination cl VI + ... + qVk = zero vector unless all ci = O. If the v's are the columns of A, the only solution to Ax = 0 is x = o.
Kronecker product (tensor product) A ® B.
Blocks aij B, eigenvalues Ap(A)Aq(B).
lA-II = l/lAI and IATI = IAI.
The big formula for det(A) has a sum of n! terms, the cofactor formula uses determinants of size n - 1, volume of box = I det( A) I.
Least squares solution X.
The vector x that minimizes the error lie 112 solves AT Ax = ATb. Then e = b - Ax is orthogonal to all columns of A.
Left nullspace N (AT).
Nullspace of AT = "left nullspace" of A because y T A = OT.
Minimal polynomial of A.
The lowest degree polynomial with meA) = zero matrix. This is peA) = det(A - AI) if no eigenvalues are repeated; always meA) divides peA).
If N NT = NT N, then N has orthonormal (complex) eigenvectors.
Outer product uv T
= column times row = rank one matrix.
The diagonal entry (first nonzero) at the time when a row is used in elimination.
Triangle inequality II u + v II < II u II + II v II.
For matrix norms II A + B II < II A II + II B II·
Volume of box.
The rows (or the columns) of A generate a box with volume I det(A) I.