CHEM 405 CUA: Science Communication | StudySoup

PreparED Study Materials

CHEM 405: Science Communication

School: Catholic University of America

Number of Notes and Study Guides Available: 0

Videos

Determining Formula Mass: Step-by-Step Approach Using Atomic Masses
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Discover the method to determine the formula mass for various compounds. Learn about the importance of atomic masses and their role in compounds like Aluminium sulfate, Diphosphorus Trioxide, and more. Understand the step-by-step approach to accurately calculate molecular weights.

Determining Neutrons from Atomic & Mass Numbers: A Comprehensive Guide
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Understand the relationship between atomic number, mass number, and neutrons within atoms. This video breaks down the simple calculation to determine the number of neutrons for specific elements like Nickel, Uranium, Scandium, and Argon.

Understanding Barometers: How Do They Measure Pressure?
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Join us in this enlightening video as we delve into the inner workings of barometers. Discover how these essential weather instruments operate, using a column of mercury to measure pressure. We'll explore the principles behind this ingenious device and help you understand the science behind pressure measurement. Whether you're a weather enthusiast or a science lover, this video will provide valuable insights into the fascinating world of barometers.

Calculate oxygen molar concentration in water at 25°C with a partial p
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This video explores molar concentration (molarity) and demonstrates the calculation of oxygen's molar concentration in water at 25°C, considering a partial pressure of 0.22 atm by employing Henry's Law and the given Henry's Law constant for oxygen, revealing that under these conditions, there are 2.86 x 10?? moles of oxygen per liter of water, highlighting the significance of understanding these concepts for managing gas dissolution in liquids across varying circumstances.

Perfecting Perbromate Ion: Achieving Zero Formal Charges
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Learn how to create a Lewis structure for the perbromate ion, ensuring all atoms achieve zero formal charges. Follow the step-by-step guide to understand the bonding and electron distribution in this chemical compound.

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