CHEM 188 KU: CHEM 188 | StudySoup

PreparED Study Materials

CHEM 188: CHEM 188

School: Kansas

Number of Notes and Study Guides Available: 1

Notes

Videos

Determining Moles of Released Ions in Dissolution Reactions
Stars

Want To Learn More? To watch the entire video and ALL of the videos in the series:

Subscribe to view the
full solution

When an ionic compound dissolves in water, it undergoes dissociation into its constituent ions. The total moles of ions released is determined by adding up the moles of each ion generated during this dissociation process. In the case of (a) disodium hydrogen phosphate (Na?HPO?), it dissociates into two sodium ions and one hydrogen phosphate ion. For (b) copper(II) sulfate pentahydrate (CuSO? · 5H?O), it dissociates into one copper ion and one sulfate ion. In (c), nickel(II) chloride (NiCl?) diss

Lewis Structures with Atom Connections & Charges
Stars

Want To Learn More? To watch the entire video and ALL of the videos in the series:

Subscribe to view the
full solution

Learn how to create Lewis structures for various molecules and assign charges where needed. Understand the molecular connectivity and electron distribution.

Pure Substances vs. Mixtures: Classifying Based on Composition & Distr
Stars

Want To Learn More? To watch the entire video and ALL of the videos in the series:

Subscribe to view the
full solution

Understand the fundamental distinctions between pure substances and mixtures. Unpack the definitions and real-world examples of elements, compounds, homogeneous, and heterogeneous mixtures.

Ethylene Glycol & Freezing Point in Antifreeze
Stars

Want To Learn More? To watch the entire video and ALL of the videos in the series:

Subscribe to view the
full solution

We explore the impact of increasing the concentration of ethylene glycol in an antifreeze mixture, explaining the resulting effect on the freezing point of the solution by examining its interaction with water molecules.

Finding NaOH Molarity: Titration of 0.200L SO?-Derived H?SO? Solution
Stars

Want To Learn More? To watch the entire video and ALL of the videos in the series:

Subscribe to view the
full solution

Determine the molarity of a NaOH solution through titration with sulfurous acid. Starting with the ideal gas equation we derive the concentration of a 0.200L SO?-derived H?SO? solution. Concluding with a molarity of 1.64 M for NaOH using calculated values.

Stars

Want To Learn More? To watch the entire video and ALL of the videos in the series:

Subscribe to view the
full solution

Textbook Solutions (0)

Top Selling Study Tools

×

Login

Organize all study tools for free

Or continue with
×

Register

Sign up for access to all content on our site!

Or continue with

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back