CHEM 224 UW: Organic Chemistry Short Program | StudySoup

PreparED Study Materials

CHEM 224: Organic Chemistry Short Program

School: University of Washington

Number of Notes and Study Guides Available: 3

Notes

Videos

Molecular Geometry & Polarity: Why CO? & CCl? Are Nonpolar Explained
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Uncover the intriguing relationship between molecular geometry and polarity in chemistry. Using CO? and CCl? as examples, learn how polar bonds can result in nonpolar molecules. Recognize the role of symmetry in determining molecular polarity.

Comparing Structural Features of Sphingomyelins and Glycolipids
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This video explores the structural and functional differences between sphingomyelins and glycolipids, two types of lipids found in cell membranes, highlighting their commonalities in backbone and fatty acid composition and their distinctive roles in cell structure and recognition.

Lone Pair vs. Bonding Pair Electrons: Atomic Insights Unveiled
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Explore the atomic world and the crucial distinctions between lone pair and bonding pair electrons in this insightful video. Delve into the fundamental aspects of atomic structure, electron orbitals, and their roles in chemical bonding, reactivity, and molecule formation.

pAg in KI & AgNO3 Titration: Exploring 39mL & 44.30mL Volumes
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Exploring the titration of 25.00 mL of 0.08230 M KI with 0.05110 M AgNO3. This video breaks down the calculation process for the potential of silver ion at various volumes of added AgNO3: 39.00 mL equivalence point and 44.30 mL. With clear steps and using the solubility product constant understand how the potential of silver ion is determined for each scenario.

Protons reveal electron count in atoms. Which statement applies?
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In this video, we explore the information that knowledge of the number of protons in a neutral element's atom can provide. Options for determining neutron count, electron count, and identifying the element's name are examined, with a conclusion that it allows us to know both the number of electrons and the element's name.

Molecule Count in 0.334 g of C?H?: Ethane Analysis
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This instructional video guides you through the process of determining the number of molecules in a given sample. It illustrates the conversion from grams to moles using the molar mass of the substance and then to molecules using Avogadro's number, providing a practical example with ethane (C?H?) to calculate approximately 6.67 x 10²¹ molecules in a 0.334 g sample.

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