CHEM 10962 KSU: General Chemistry 2 | StudySoup

PreparED Study Materials

CHEM 10962: General Chemistry 2

School: Kent State University

Number of Notes and Study Guides Available: 1

Notes

Videos

Lattice Energy: Always Positive; Hydration Energy: Always Negative
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In this video we clarify why lattice energy in solids is always a positive value due to the energy needed to separate ions making it an endothermic process. On the flip side hydration energy is always negative as it releases heat when ions dissolve in water making it an exothermic reaction. We use sodium chloride as a real-world example to illustrate these crucial thermodynamic concepts

Pure Substances vs. Mixtures: Classifying Based on Composition & Distr
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Understand the fundamental distinctions between pure substances and mixtures. Unpack the definitions and real-world examples of elements, compounds, homogeneous, and heterogeneous mixtures.

Calculating Density: Rectangular Metal Bar & Significance
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Learn the process of determining the density of a rectangular metal bar using its measurements. Understand how volume and mass play a crucial role in the calculation, and the importance of representing results with the correct number of significant figures

Diluting a 5.5 M KCl Solution to 0.100 M
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Learn the steps to make a 2.5 L of 0.100 M KCl solution from a 5.5 M stock solution in this easy-to-follow tutorial.

Quantitative vs Non-Quantitative: Precision in Scientific Observations
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Unpack the difference between quantitative and non-quantitative observations. Examples include a person's weight on the Moon and the depth a hand pump can reach. Learn why precise measurements are crucial in scientific studies.

Molecule Count in 0.334 g of C?H?: Ethane Analysis
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This instructional video guides you through the process of determining the number of molecules in a given sample. It illustrates the conversion from grams to moles using the molar mass of the substance and then to molecules using Avogadro's number, providing a practical example with ethane (C?H?) to calculate approximately 6.67 x 10²¹ molecules in a 0.334 g sample.

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