Three single-phase two-winding transformers, each rated 25

Chapter , Problem 3.36

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QUESTION:

Three single-phase two-winding transformers, each rated 25 MVA, 34.5/13.8 kV, are connected to form a three-phase \(\Delta-\Delta\) bank. Balanced positive-sequence voltages are applied to the high-voltage terminals, and a balanced, resistive Y load connected to the low-voltage terminals absorbs 75 MW at 13.8 kV. If one of the single-phase transformers is removed (resulting in an \(\text { open- } \Delta\) connection) and the balanced load is simultaneously reduced to 43.3 MW (57.7% of the original value), determine

(a) the load voltages \(V_{a n}, V_{b n}, \text { and } V_{c n}\);

(b) load currents \(I_{a}, I_{b}, \text { and } I_{c}\); and

(c) the MVA supplied by each of the remaining two transformers. Are balanced voltages still applied to the load? Is the \(\text { open- } \Delta\) transformer overloaded?

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QUESTION:

Three single-phase two-winding transformers, each rated 25 MVA, 34.5/13.8 kV, are connected to form a three-phase \(\Delta-\Delta\) bank. Balanced positive-sequence voltages are applied to the high-voltage terminals, and a balanced, resistive Y load connected to the low-voltage terminals absorbs 75 MW at 13.8 kV. If one of the single-phase transformers is removed (resulting in an \(\text { open- } \Delta\) connection) and the balanced load is simultaneously reduced to 43.3 MW (57.7% of the original value), determine

(a) the load voltages \(V_{a n}, V_{b n}, \text { and } V_{c n}\);

(b) load currents \(I_{a}, I_{b}, \text { and } I_{c}\); and

(c) the MVA supplied by each of the remaining two transformers. Are balanced voltages still applied to the load? Is the \(\text { open- } \Delta\) transformer overloaded?

ANSWER:

Step 1 of 5

Calculate the  \(3 - \phi   kVA ratings {S_{3\phi }}\).

\({S_{3\phi }} = 3{S_{1\phi }}\)

\({S_{3\phi }} = 3\left( {25} \right)\)

\({S_{3\phi }} = 75\;{\rm{MVA}}\)

Calculate the line-line voltage rating.

\(\frac{{{V_{HLL}}}}{{{V_{XLL}}}} = \frac{{\left( {34.5} \right)\sqrt 3 }}{{\left( {13.8} \right)\sqrt 3 }} = \frac{{59.756}}{{23.90}}\)

Calculate the line-line voltage rating for each single-phase transformer.

\(\frac{{{V_{HLL}}}}{{{V_{XLL}}}} = \frac{{\frac{{59.756}}{3}}}{{\frac{{23.90}}{3}}}\)

\(\frac{{{V_{HLL}}}}{{{V_{XLL}}}} = \frac{{19.9\;{\rm{kV}}}}{{7.96\;{\rm{kV}}}}\)

Assume Base values as the ratings of the transformer.

Base value of voltage in Low voltage side, \({V_{{\rm{base,XLL}}}} = 7.96\;{\rm{kV}}\).

Base value KVA rating, \({S_{{\rm{base}},3 - \phi }} = 75\;{\rm{MVA}}\).

Step 2 of 5

(a)

Apply balanced Positive sequence voltages to these connections.

\({V_{ab}} + {V_{bc}} + {V_{ca}} = 0\)

Calculate the load voltages of Y -connection resistive load.

\({V_{an}} = \frac{{{V_{ab}}}}{{\sqrt 3 }}\)

\({V_{an}} = \frac{{13.8\;{\rm{kV}}}}{{\sqrt 3 }}\)

\({V_{an}} = 7.96\angle 0^\circ \;{\rm{kV}}\)

Similarly,

\({V_{bn}} = 7.96\angle  - 120^\circ \;{\rm{kV}}\)

\({V_{cn}} = 7.96\angle 120^\circ \;{\rm{kV}}\)

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