A jet plane traveling 1890 km/h (525 m/s) pulls out of a

Chapter 18, Problem 2P

(choose chapter or problem)

Get Unlimited Answers
QUESTION:

Problem 2P

A jet plane traveling 1890 km/h (525 m/s) pulls out of a dive by moving in an arc of radius 6.00 km. What is the plane’s acceleration in g’s?

Questions & Answers

QUESTION:

Problem 2P

A jet plane traveling 1890 km/h (525 m/s) pulls out of a dive by moving in an arc of radius 6.00 km. What is the plane’s acceleration in g’s?

ANSWER:

Solution: To calculate magnitude and direction of third rope,we can use newton’s second law it states the total net force is equal to mass and acceleration of the body. F = ma (m) is mass of the body and (a) is acceleration of the body. Below figure shows the free body diagram of the rope system. In The above figure shows the force in rope 1 and rope 2 must balance the force in rope 3.rope 3 is an angle needs to break the x and y-direction

Add to cart


Study Tools You Might Need

Not The Solution You Need? Search for Your Answer Here:

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back