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A jet plane traveling 1890 km/h (525 m/s) pulls out of a
Chapter 18, Problem 2P(choose chapter or problem)
Problem 2P
A jet plane traveling 1890 km/h (525 m/s) pulls out of a dive by moving in an arc of radius 6.00 km. What is the plane’s acceleration in g’s?
Questions & Answers
QUESTION:
Problem 2P
A jet plane traveling 1890 km/h (525 m/s) pulls out of a dive by moving in an arc of radius 6.00 km. What is the plane’s acceleration in g’s?
ANSWER:
Solution: To calculate magnitude and direction of third rope,we can use newton’s second law it states the total net force is equal to mass and acceleration of the body. F = ma (m) is mass of the body and (a) is acceleration of the body. Below figure shows the free body diagram of the rope system. In The above figure shows the force in rope 1 and rope 2 must balance the force in rope 3.rope 3 is an angle needs to break the x and y-direction