A mass on the end of a spring is oscillating with angular | StudySoup

Textbook Solutions for Classical Mechanics

Chapter 5 Problem 5.6

Question

A mass on the end of a spring is oscillating with angular frequency \(\omega\). At t = 0, its position is \(x_{0}>0\) and I give it a kick so that it moves back toward the origin and executes simple harmonic motion with amplitude \(2 x_{0}\). Find its position as a function of time in the form (III) of Problem 5.5.

Solution

Step 1 of 4

The equation of simple harmonic motion is given as:

\(x(t)=A \cos (\omega t-\delta) \ldots \ldots(1)\)

At \(t=0\) the position is \(x_{0}\). Therefore, the above equation can be written as:

\(\begin{aligned}
x_{0} & =A \cos (-\delta) \\
& =A \cos \delta
\end{aligned}\)

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full solution

Title Classical Mechanics 0 
Author John R Taylor
ISBN 9781891389221

A mass on the end of a spring is oscillating with angular

Chapter 5 textbook questions

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