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Quantitative Chemical Analysis | 8th Edition | ISBN: 9781429218153 | Authors: Daniel C. Harris
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In olden days, mercury cells with the following chemistry were used to power heart

Chapter 13, Problem 13-A

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QUESTION:

In olden days, mercury cells with the following chemistry were used to power heart pacemakers:

\(\mathrm{Zn}(s)+\mathrm{HgO}(s) \rightarrow \mathrm{ZnO}(s)+\mathrm{Hg}(l) \quad E^{\circ}=1.35 \mathrm{~V}\)

What is the cell voltage? If the power required to operate the pacemaker is 0.010 0 W, how many kilograms of HgO (FM 216.59) will be consumed in 365 days? How many pounds of HgO is this? (1 pound = 453.6 g)

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QUESTION:

In olden days, mercury cells with the following chemistry were used to power heart pacemakers:

\(\mathrm{Zn}(s)+\mathrm{HgO}(s) \rightarrow \mathrm{ZnO}(s)+\mathrm{Hg}(l) \quad E^{\circ}=1.35 \mathrm{~V}\)

What is the cell voltage? If the power required to operate the pacemaker is 0.010 0 W, how many kilograms of HgO (FM 216.59) will be consumed in 365 days? How many pounds of HgO is this? (1 pound = 453.6 g)

ANSWER:

Step 1 of 5

The given reaction is:

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