Solved: The period T of a simple pendulum is given by T = 2 L/g where L is the length of
Chapter 3, Problem 5(choose chapter or problem)
The period \(T\) of a simple pendulum is given by \(T=2 \pi \sqrt{L / g}\) where \(L\) is the length of the pendulum and \(g\) is the acceleration due to gravity.
a. Assume \(g=9.80 \mathrm{~m} / \mathrm{s}^{2}\) exactly, and that \(L=0.742 \pm 0.005 \mathrm{~m}\). Estimate \(T\), and find the uncertainty in the estimate.
b. Assume \(L=0.742 \mathrm{~m}\) exactly, and that \(T=1.73 \pm 0.01 \mathrm{~s}\). Estimate g, and find the uncertainty in the estimate.
Equation Transcription:
Text Transcription:
T
T=2 \pi \sqrt{L / g}
L
g
g=9.80 m s^2
L=0.742 \pm 0.005 m
T
L=0.742 m
T=1.73 \pm 0.01 s
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