Get answer: The following MINITAB output presents the results of a hypothesis test for

Chapter 6, Problem 12

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The following MINITAB output presents the results of a hypothesis test for the difference \(\mu_{X}-\mu_{Y}\) between two population means:

Two-sample T for X vs Y

N Mean StDev SE Mean

X 135 3.94 2.65 0.23

Y 180 4.43 2.38 0.18

Difference = mu (X) − mu (Y)

Estimate for difference: −0.484442

95% upper bound for difference: −0.007380

T-Test of difference = 0 (vs <): T-Value = −1.68 P-Value = 0.047 DF = 270

a. Is this a one-tailed or two-tailed test?

b. What is the null hypothesis?

c. Can \(H_0\) be rejected at the 5% level? How can you tell?

d. The output presents a Student’s t test. Compute the P-value using a z test. Are the two results similar?

e. Use the output and an appropriate table to compute a 99% confidence interval for \(\mu_{X}-\mu_{Y}\) based on the z statistic.

Equation Transcription:

Text Transcription:

{mu}X-{mu}Y

H_0

{mu}X-{mu}Y

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