Get answer: The following MINITAB output presents the results of a hypothesis test for
Chapter 6, Problem 12(choose chapter or problem)
The following MINITAB output presents the results of a hypothesis test for the difference \(\mu_{X}-\mu_{Y}\) between two population means:
Two-sample T for X vs Y
N Mean StDev SE Mean
X 135 3.94 2.65 0.23
Y 180 4.43 2.38 0.18
Difference = mu (X) − mu (Y)
Estimate for difference: −0.484442
95% upper bound for difference: −0.007380
T-Test of difference = 0 (vs <): T-Value = −1.68 P-Value = 0.047 DF = 270
a. Is this a one-tailed or two-tailed test?
b. What is the null hypothesis?
c. Can \(H_0\) be rejected at the 5% level? How can you tell?
d. The output presents a Student’s t test. Compute the P-value using a z test. Are the two results similar?
e. Use the output and an appropriate table to compute a 99% confidence interval for \(\mu_{X}-\mu_{Y}\) based on the z statistic.
Equation Transcription:
Text Transcription:
{mu}X-{mu}Y
H_0
{mu}X-{mu}Y
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