?Prove that $\lim _{x \rightarrow a} \sqrt{x}=\sqrt{a}$ if $a>0$. \(\left[\text {

Chapter 2, Problem 37

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Prove that $\lim _{x \rightarrow a} \sqrt{x}=\sqrt{a}$ if $a>0$.

$\left[\text { Hint: Use }|\sqrt{x}-\sqrt{a}|=\frac{|x-a|}{\sqrt{x}+\sqrt{a}}\right]$

Equation Transcription:

$\lim\limits_{{x} \rightarrow {a}}\sqrt{x}=\sqrt{a}$

$a>0$

| $\sqrt{x}-\sqrt{a\ }|=\frac{|x\ -a|}{\sqrt{x\ }+\ \sqrt{a}}$

Text Transcription:

lim_x right arrow a square root x=square root a

a>0

|square root x-square root a |=|x -a|/square root x +square root a

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?Prove that \(\lim _{x \rightarrow a} \sqrt{x}=\sqrt{a}\) if \(a>0\). \(\left[\text {