?If the function f is defined by\(f(x)= \begin{cases}0 & \text { if } x \text { is
Chapter 2, Problem 39(choose chapter or problem)
If the function f is defined by
\(f(x)= \begin{cases}0 & \text { if } x \text { is rational } \\ 1 & \text { if } x \text { is irrational }\end{cases}\)
prove that \(\lim _{x \rightarrow 0} f(x)\) does not exist.
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