?Find the derivative of the function.\(g(x)=\int_{2 x}^{3 x} \frac{\mu^{2}-1}{u^{2}+1} d

Chapter 4, Problem 67

(choose chapter or problem)

Find the derivative of the function.

$g(x)=\int_{2 x}^{3 x} \frac{\mu^{2}-1}{u^{2}+1} d u$

$\left[\text { Hint }: \int_{2 x}^{3 x} f(u) d u=\int_{2 x}^{0} f(u) d u+\int_{0}^{3 x} f(u) d u\right]$

Equation Transcription:

$g(x)=\int\limits_{2x}^{3x}\frac{{u}^{2}-1}{{u}^{2}+1}du$

$\int\limits_{2x}^{3x}f(u)\ du=\int\limits_{2x}^{0}f(u)du+\int\limits_{0}^{3x}f(u)du$

Text Transcription:

g(x)=integral _2x ^3x u^2-1/u^2+1 du

integral_2x ^3x f(u)du=integral _2x ^0 f(u)du+integral _0 ^3x f(u)du

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