?(a) Suppose that \(\Sigma a_{n}\) and \(\Sigma b_{n}\) are series with positive terms

Chapter 10, Problem 49

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QUESTION:

(a) Suppose that \(\Sigma a_{n}\) and \(\Sigma b_{n}\) are series with positive terms and \(\Sigma b_{n}\) is divergent. Prove that if

\(\lim _{n \rightarrow \infty} \frac{a_{n}}{b_{n}}=\infty\)

then \(\Sigma a_{n}\) is also divergent.

(b) Use part (a) to show that the series diverges.

(i) \( \sum_{n=2}^{\infty} \frac{1}{\ln n}\)

(ii) \(\sum_{n=1}^{\infty} \frac{l n n}{n}\)

Questions & Answers

QUESTION:

(a) Suppose that \(\Sigma a_{n}\) and \(\Sigma b_{n}\) are series with positive terms and \(\Sigma b_{n}\) is divergent. Prove that if

\(\lim _{n \rightarrow \infty} \frac{a_{n}}{b_{n}}=\infty\)

then \(\Sigma a_{n}\) is also divergent.

(b) Use part (a) to show that the series diverges.

(i) \( \sum_{n=2}^{\infty} \frac{1}{\ln n}\)

(ii) \(\sum_{n=1}^{\infty} \frac{l n n}{n}\)

ANSWER:

Step 1 of 3

a)

Given that and are series with positive terms and is divergent, and also we have:

                                                             

Since, then for every, there is a, so that every  we have:

                                                     

From here, sincediverges, then so does the series.

Using the comparison test, we can say that diverges as well.

Thus, it is proved thatis also divergent.

 

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