Find dz/dt in two ways: by using the Chain Rule, and by first substituting the expressions for x and y to write z as a function of t. Do your answers agree? z = x2y + xy2, x = 3t, y = t2
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Textbook Solutions for Calculus: Early Transcendentals
Question
Homogeneous Functions A function f is called homogeneous of degree n if it satisfies the equation
\(f(t x, t y)=t^n f(x, y)\)
for all t, where n is a positive integer and f has continuous second-order partial derivatives.
Show that if f is homogeneous of degree n, then
(a) \(x \frac{\partial f}{\partial x}+y \frac{\partial f}{\partial y}=n f(x, y)\)
[Hint: Use the Chain Rule to differentiate f(t x, t y) with respect to t.]
(b) \(x^2 \frac{\partial^2 f}{\partial x^2}+2 x y \frac{\partial^2 f}{\partial x \partial y}+y^2 \frac{\partial^2 f}{\partial y^2}=n(n-1) f(x, y)\)
Solution
The first step in solving 14.5 problem number trying to solve the problem we have to refer to the textbook question: Homogeneous Functions A function f is called homogeneous of degree n if it satisfies the equation\(f(t x, t y)=t^n f(x, y)\)for all t, where n is a positive integer and f has continuous second-order partial derivatives.Show that if f is homogeneous of degree n, then(a) \(x \frac{\partial f}{\partial x}+y \frac{\partial f}{\partial y}=n f(x, y)\)[Hint: Use the Chain Rule to differentiate f(t x, t y) with respect to t.](b) \(x^2 \frac{\partial^2 f}{\partial x^2}+2 x y \frac{\partial^2 f}{\partial x \partial y}+y^2 \frac{\partial^2 f}{\partial y^2}=n(n-1) f(x, y)\)
From the textbook chapter The Chain Rule you will find a few key concepts needed to solve this.
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