?The integral $\iint_{R} \sqrt{9-y^{2}} d A$, where $R=[0,4] \times[0,2]$

Chapter 13, Problem 12

(choose chapter or problem)

The integral $\iint_{R} \sqrt{9-y^{2}} d A$, where $R=[0,4] \times[0,2]$, represents the volume of a solid. Sketch the solid.

Equation Transcription:

$\int\limits_{\ }^{\ }\int\limits_{R}^{\ }\sqrt{9-{y}^{2}}dA$

$R=[0,4]\times{}[0,2]$

Text Transcription:

double integral_R sqrt 9-y^2 dA

R=[0, 4]x[0, 2]

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?The integral \(\iint_{R} \sqrt{9-y^{2}} d A\), where \(R=[0,4] \times[0,2]\)