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Domain and range Graph each function with a | Ch 1.1 - 14E

Calculus: Early Transcendentals | 1st Edition | ISBN: 9780321570567 | Authors: William L. Briggs, Lyle Cochran, Bernard Gillett ISBN: 9780321570567 2

Solution for problem 14E Chapter 1.1

Calculus: Early Transcendentals | 1st Edition

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Calculus: Early Transcendentals | 1st Edition | ISBN: 9780321570567 | Authors: William L. Briggs, Lyle Cochran, Bernard Gillett

Calculus: Early Transcendentals | 1st Edition

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Problem 14E

Domain and range Graph each function with a graphing utility using the given window: Then state the domain and range of the function. y+1 g(y) = y ?y?6, [? 4,6] × [? 3,3]

Step-by-Step Solution:

Step by step solution Step 1 of 2 The denominator of function g cannot be equal to zero. y y6 = / 0 ………..(1) 2 If we solve the equation y y6 = 0 we get two solutions, -2 and 3. Based on the inequality (1) we can conclude that the function g (x) is not de ed at = -2 and = 3 and its domain is {y : y /2,3}. The function g(x) takes all the values in R therefore the range is all the numbers in . A graphic utility does not represent this function acurately.

Step 2 of 2

Chapter 1.1, Problem 14E is Solved
Textbook: Calculus: Early Transcendentals
Edition: 1
Author: William L. Briggs, Lyle Cochran, Bernard Gillett
ISBN: 9780321570567

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Domain and range Graph each function with a | Ch 1.1 - 14E

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