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Solved: An anesthetic gas contains 64.81% carbon, 13.60%
Chapter 5, Problem 5.98(choose chapter or problem)
QUESTION:
An anesthetic gas contains 64.81% carbon, 13.60% hydrogen, and 21.59% oxygen, by mass. If 2.00 L of the gas at 25 C and 0.420 atm weighs 2.57 g, what is the molecular formula of the anesthetic?
Questions & Answers
QUESTION:
An anesthetic gas contains 64.81% carbon, 13.60% hydrogen, and 21.59% oxygen, by mass. If 2.00 L of the gas at 25 C and 0.420 atm weighs 2.57 g, what is the molecular formula of the anesthetic?
ANSWER:Step 1 of 5
We will use empirical formula and ideal gas equation to find the molecular formula of the anesthetic.
Given:
\(\begin{array}{l}
P=0.420 \mathrm{~atm} \\
T=25 C=298 K \\
V=2.0 L \\
m=2.57 g
\end{array}\)
Ideal gas equation is:
\(P V=n R T\)