Solved: An anesthetic gas contains 64.81% carbon, 13.60%

Chapter 5, Problem 5.98

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QUESTION:

An anesthetic gas contains 64.81% carbon, 13.60% hydrogen, and 21.59% oxygen, by mass. If 2.00 L of the gas at 25 C and 0.420 atm weighs 2.57 g, what is the molecular formula of the anesthetic?

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QUESTION:

An anesthetic gas contains 64.81% carbon, 13.60% hydrogen, and 21.59% oxygen, by mass. If 2.00 L of the gas at 25 C and 0.420 atm weighs 2.57 g, what is the molecular formula of the anesthetic?

ANSWER:

Step 1 of 5

We will use empirical formula and ideal gas equation to find the molecular formula of the anesthetic. 

Given:

\(\begin{array}{l}
P=0.420 \mathrm{~atm} \\
T=25 C=298 K \\
V=2.0 L \\
m=2.57 g
\end{array}\)

Ideal gas equation is:

\(P V=n R T\)

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