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University Physics, Volume 3 | 17th Edition | ISBN: 9781938168185 | Authors: Samuel J. Ling ISBN: 9781938168185 2032

Solution for problem 29 Chapter 1

University Physics, Volume 3 | 17th Edition

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University Physics, Volume 3 | 17th Edition | ISBN: 9781938168185 | Authors: Samuel J. Ling

University Physics, Volume 3 | 17th Edition

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Problem 29

The Propagation of Light

In what substance in Table 1.1 light is the speed of \(2.290 \times 10^{8} \mathrm{~m} / \mathrm{s} ?\)?

Text Transcription:

2.290 times 10^8 m/s

Step-by-Step Solution:
Step 1 of 3

Day 12 ­ 2/1/2016 Topics for Midterm ­ fluids of all kinds, not differential equations ­ harmonic oscillator, up to damping ­ simple harmonic motion ­ some problems with damping and resonance after exam ­ Read 15.1, 15.2, 15.4 Waves y(x, t) = Asin(kx ­ wt) displacement amplitude of displacement t = 0 y(x, t) = Asin(kx) x = 0 y(x=0, t) = Asin(­wt) = ­Asin(wt) y(x, t=0) = y(x + λ, t=0) Asin(kx) = Asin[k(x+λ)] kλ = 2π 2π The wave number k = γ Asin(wt) = Asin[w(t+T)] wT = 2π → w = 2π = rad angular frequency T s frequency f → f = T1 Ex. v​w​= 0.5 cm/s A = 1cm T = 8s λ = 4cm k = π rad ω = 2π = π rad 2 cm T 4 cm y(x, t) = 1 cm sin ( π rax − π rat) 2 cm 4 s verify, does 4(x = 0, t = 0) = graphs says no! Initial Phase Phase φ = kx − ωt y(x,t) = Asin(φ + φ )o π π π sin(kx ­ ωt+ )2= sin(φ)cos( ) + c2s(φ)sin( ) 2 Ex. y(x, t) = Asin(kx ­ wt) = Asin(x ­ t)k = 1, w = 1 t = 0 y(x, 0) = Asinx t = π y(x, ) = Asin(x ­ ) = Asinxcos( ) ­ Acosxsin( ) π 2 2 2 2 2 y(x, ) = ­Acosx 2 y = Asin(kx ­ wt)

Step 2 of 3

Chapter 1, Problem 29 is Solved
Step 3 of 3

Textbook: University Physics, Volume 3
Edition: 17
Author: Samuel J. Ling
ISBN: 9781938168185

This full solution covers the following key subjects: . This expansive textbook survival guide covers 11 chapters, and 1216 solutions. This textbook survival guide was created for the textbook: University Physics, Volume 3 , edition: 17. Since the solution to 29 from 1 chapter was answered, more than 202 students have viewed the full step-by-step answer. The answer to “?The Propagation of LightIn what substance in Table 1.1 light is the speed of \(2.290 \times 10^{8} \mathrm{~m} / \mathrm{s} ?\)?Text Transcription:2.290 times 10^8 m/s” is broken down into a number of easy to follow steps, and 25 words. The full step-by-step solution to problem: 29 from chapter: 1 was answered by Aimee Notetaker, our top Physics solution expert on 03/18/22, 10:28AM. University Physics, Volume 3 was written by Aimee Notetaker and is associated to the ISBN: 9781938168185.

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