?The Compton EffectShow that \(p=h / \lambda \text { and } E_{f}=h f\) are consistent
Chapter 6, Problem 85(choose chapter or problem)
The Compton Effect
Show that \(p=h / \lambda \text { and } E_{f}=h f\) are consistent with the relativistic formula \(E^{2}=p^{2} c^{2}+m_{0}^{2} c^{2}\).
Text Transcription:
p=h/lambda and E_f=hf
E^2=p^2c^2+m_0^2 c^2
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