×
Get Full Access to Chemistry: The Central Science - 14 Edition - Chapter 14 - Problem 14.24
Get Full Access to Chemistry: The Central Science - 14 Edition - Chapter 14 - Problem 14.24

×

# ?For each of the following gas-phase reactions, write the rate expression in terms of the appearance of each product and disappearance of each reactant

ISBN: 9780134414232 1274

## Solution for problem 14.24 Chapter 14

Chemistry: The Central Science | 14th Edition

• Textbook Solutions
• 2901 Step-by-step solutions solved by professors and subject experts
• Get 24/7 help from StudySoup virtual teaching assistants

Chemistry: The Central Science | 14th Edition

4 5 1 376 Reviews
25
5
Problem 14.24

For each of the following gas-phase reactions, write the rate expression in terms of the appearance of each product and disappearance of each reactant:

(a) $$2 \mathrm{H}_{2} \mathrm{O}(g) \longrightarrow 2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g)$$

(b) $$2 \mathrm{SO}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{SO}_{3}(g)$$

(c) $$2 \mathrm{NO}(g)+2 \mathrm{H}_{2}(g) \longrightarrow \mathrm{N}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(g)$$

(d) $$\mathrm{N}_{2}(g)+2 \mathrm{H}_{2}(g) \longrightarrow \mathrm{N}_{2} \mathrm{H}_{4}(g)$$

Text Transcription:

2 H2O(g) \longrightarrow 2 H2(g) + O2(g)

2 SO2(g) + O2(g) \longrightarrow 2 SO3(g)

2 NO(g) + 2 H2(g) \longrightarrow N2(g) + 2 H2O(g)

N2(g) + 2 H2(g) \longrightarrow N2H4(g)

Step-by-Step Solution:

Step 1 of 5) Atmospheric pressure decreases with increasing elevation (Figure 18.1), declining much more rapidly at lower elevations than at higher ones because of the atmosphere’s compressibility. Thus, the pressure decreases from an average value of 760 torr at sea level to 2.3 * 10-3 torr at 100 km, to only 1.0 * 10-6 torr at 200 km. The troposphere and stratosphere together account for 99.9% of the mass of the atmosphere, 75% of which is the mass in the troposphere. Nevertheless, the thin upper atmosphere plays many important roles in determining the conditions of life at the surface.Earth’s atmosphere is constantly bombarded by radiation and energetic particles from the Sun. This barrage of energy has profound chemical and physical effects, especially in the upper regions of the atmosphere, above about 80 km (Figure 18.2). In addition, because of Earth’s gravitational field, heavier atoms and molecules tend to sink in the atmosphere, leaving lighter atoms and molecules at the top of the atmosphere. (This is why, as just noted, 75% of the atmosphere’s mass is in the troposphere.) Because of all these factors, the composition of the atmosphere is not uniform. Table 18.1 shows the composition of dry air near sea level. Note that although traces of many substances are present, N2 and O2 make up about 99% of sea-level air. The noble gases and CO2 make up most of the remainder.

Step 2 of 2

## Discover and learn what students are asking

Calculus: Early Transcendental Functions : Graphs and Models
?In Exercises 5-14, sketch the graph of the equation by point plotting. $$y=4-x^{2}$$

Calculus: Early Transcendental Functions : Product and Quotient Rules and Higher-Order Derivatives
?Using the Product Rule In Exercises 1–6, use the Product Rule to find the derivative of the function. $$f(x)=e^{x} \cos x$$

Calculus: Early Transcendental Functions : Conservative Vector Fields and Independence of Path
?In Exercises 5 - 10, determine whether the vector field is conservative. $$\mathbf{F}(x, y)=15 x^{2} y^{2} \mathbf{i}+10 x^{3} y \mathbf{j}$$

#### Related chapters

Unlock Textbook Solution