?A particle moves on a circular path of radius b according to the function
Chapter 3, Problem 68(choose chapter or problem)
A particle moves on a circular path of radius b according to the function \(\mathbf{r}(t)=b \cos (\omega t) \mathbf{i}+b \sin (\omega t) \mathbf{j}\), where \(\omega\) is the angular velocity, \(d \theta / d t\).
Show that the speed of the particle is proportional to the angular velocity.
Text Transcription:
r(t) = b cos (omega t) i + b sin (omega t) j
omega
d theta / dt
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer