?[T] The force vector F acting on a proton with an electric charge of \(1.6 \times

Chapter 2, Problem 239

(choose chapter or problem)

[T] The force vector F acting on a proton with an electric charge of \(1.6 \times 10^{-19} \mathrm{C}\) (in coulombs) moving in a magnetic field B where the velocity vector v is given by \(\mathbf{F}=1.6 \times 10^{-19}(\mathbf{v} \times \mathbf{B})\) (here, v is expressed in meters per second, B is in tesla [T], and F is in newtons [N]). Find the force that acts on a proton that moves in the xyplane at velocity \(\mathbf{v}=10^{5} \mathbf{i}+10^{5} \mathbf{j}\) (in meters per second) in a magnetic field given by B = 0.3j.

Text Transcription:

1.6 times 10^-19 C

F = 1.6 times 10^-19 (v times B)

v = 10^5 i + 10^5 j