?Convert the \(\int_{0}^{4} \int_{0}^{\sqrt{16-x^{2}}}

Chapter 5, Problem 285

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Convert the \(\int_{0}^{4} \int_{0}^{\sqrt{16-x^{2}}} \int_{-\sqrt{16-x^{2}-y^{2}}}^{\sqrt{16-x^{2}}}\left(x^{2}+y^{2}+z^{2}\right)^{2} d z d y d x) into an integral in spherical coordinates.

Text Transcription:

int_0^4 int_0 ^ sqrt 16-x^2 int_-sqrt 16-x^2-y^2 ^ sqrt 16-x^2 (x^2+y^2+z^2)^2 dzdydx

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