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Atkins' Physical Chemistry | 11th Edition | ISBN: 9780198769866 | Authors: Atkins, Peter; De Paula, Julio; Keeler, James ISBN: 9780198769866 2042

Solution for problem I15.1 Chapter 15

Atkins' Physical Chemistry | 11th Edition

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Atkins' Physical Chemistry | 11th Edition | ISBN: 9780198769866 | Authors: Atkins, Peter; De Paula, Julio; Keeler, James

Atkins' Physical Chemistry | 11th Edition

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Problem I15.1

Calculate the thermal expansion coefficient, \(\alpha=(\partial V / \partial T)_{p} / V\), of diamond given that the (111) reflection shifts from \(22.0403^{\circ}\) to \(21.9664^{\circ}\) on heating a crystal from 100 K to 300 K and 154.0562 pm X-rays are used.

Text Transcription:

alpha=(partial V/partial T)_p /V

22.0403^circ

21.9664^circ

Step-by-Step Solution:
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CHAPTER 15 NOTES CHAPTER 15 NOTES CHAPTER 15 NOTES CHAPTER 15 NOTES CHAPTER 15 NOTES CHAPTER 15 NOTES CHAPTER 15 NOTES CHAPTER 15 NOTES CHAPTER 15 NOTES CHAPTER 15 NOTES CHAPTER 15 NOTES CHAPTER 15 NOTES CHAPTER 15 NOTES

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Chapter 15, Problem I15.1 is Solved
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Textbook: Atkins' Physical Chemistry
Edition: 11
Author: Atkins, Peter; De Paula, Julio; Keeler, James
ISBN: 9780198769866

Since the solution to I15.1 from 15 chapter was answered, more than 205 students have viewed the full step-by-step answer. Atkins' Physical Chemistry was written by Aimee Notetaker and is associated to the ISBN: 9780198769866. This full solution covers the following key subjects: . This expansive textbook survival guide covers 327 chapters, and 1120 solutions. The answer to “?Calculate the thermal expansion coefficient, \(\alpha=(\partial V / \partial T)_{p} / V\), of diamond given that the (111) reflection shifts from \(22.0403^{\circ}\) to \(21.9664^{\circ}\) on heating a crystal from 100 K to 300 K and 154.0562 pm X-rays are used.Text Transcription:alpha=(partial V/partial T)_p /V22.0403^circ21.9664^circ” is broken down into a number of easy to follow steps, and 44 words. This textbook survival guide was created for the textbook: Atkins' Physical Chemistry, edition: 11. The full step-by-step solution to problem: I15.1 from chapter: 15 was answered by Aimee Notetaker, our top Chemistry solution expert on 04/25/22, 03:45PM.

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