?A cone-shaped tank has a cross-sectional area that increases with its depth
Chapter 6, Problem 253(choose chapter or problem)
A cone-shaped tank has a cross-sectional area that increases with its depth: \(A=\left(\pi r^{2} h^{2}\right) / H^{3}\). Show that the work to empty it is half the work for a cylinder with the same height and base.
Text Transcription:
A=(pi r^2 h^2)/H^3
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