?At 800 K, the equilibrium constant for \(\mathrm{I}_{2}(g) \rightleftharpoons 2

Chapter 15, Problem 15.49

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At 800 K, the equilibrium constant for \(\mathrm{I}_{2}(g) \rightleftharpoons 2 \mathrm{I}(g)\) is \(K_{c}=3.1 \times 10^{-5}\). If an equilibrium mixture in a 10.0-L vessel contains \(2.67 \times 10^{-2} \mathrm{~g}\) of I(g), how many grams of \(\mathrm{I}_{2}\) are in the mixture?

Text Transcription:

I_2(g) \rightleftharpoons 2 I(g)

K_c=3.1 \times 10^-5

2.67 times 10^-2 g

I_2

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