?Both the forward reaction and the reverse reaction in the following equilibrium are
Chapter 15, Problem 15.71(choose chapter or problem)
Both the forward reaction and the reverse reaction in the following equilibrium are believed to be elementary steps:
\(\mathrm{CO}(g)+\mathrm{Cl}_{2}(g) \rightleftharpoons \mathrm{COCl}(g)+\mathrm{Cl}(g)\)
At \(25^{\circ} \mathrm{C}\), the rate constants for the forward and reverse reactions are \(1.4 \times 10^{-28} \mathrm{M}^{-1} \mathrm{~s}^{-1}\) and \(9.3 \times 10^{10} \mathrm{M}^{-1} \mathrm{~s}^{-1}\), respectively.
(a) What is the value for the equilibrium constant at \(25^{\circ} \mathrm{C}\) ?
(b) Are reactants or products more plentiful at equilibrium?
Text Transcription:
CO(g)+Cl_2(g) \rightleftharpoons COCl(g)+Cl(g)
25^circ C
1.4 \times 10^-28 M^-1 s^-1
9.3 \times 10^10 M-1 s^-1
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