?Assuming that the vibrations of a \({ }^{35} \mathrm{Cl}_{2}\) molecule are equivalent

Chapter 7, Problem E7E.5(a)

(choose chapter or problem)

Assuming that the vibrations of a \({ }^{35} \mathrm{Cl}_{2}\) molecule are equivalent to those of a harmonic oscillator with a force constant \(k_{\mathrm{f}}=329 \mathrm{Nm}^{-1}\), what is the zero-point energy of vibration of this molecule? Use \(m\left({ }^{35} \mathrm{Cl}\right)=34.9688 m_{\mathrm{u}}\).

Text Transcription:

35Cl_2

k_f= 329Nm^−1

m^(35Cl) = 34.9688m_u

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