?The classical turning points of a harmonic oscillator occur at the displacements at

Chapter 7, Problem E7E.6(a)

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The classical turning points of a harmonic oscillator occur at the displacements at which all of the energy is potential energy; that is, when \(E_{v}=\frac{1}{2} k_{\mathrm{p}} x_{\mathrm{tp}}^{2}\). For a particle of mass \(m_{\mathrm{u}}\) undergoing harmonic motion with force constant \(k_{\mathrm{f}}=1000 \mathrm{Nm}^{-1}\), calculate the energy of the state with v = 0 and hence find the separation between the classical turning points. Repeat the

calculation for an oscillator with \(k_{f}=100 \mathrm{Nm}^{-1}\).

Text Transcription:

E_v = 1/2 k_p x_tp^2

m_u

k_f = 1000Nm^−1

k_f = 100Nm^−1

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