?Liquid isobutane is throttled through a valve from an initial state of 360 K and 4000
Chapter 6, Problem 6.8(choose chapter or problem)
Liquid isobutane is throttled through a valve from an initial state of 360 K and 4000 kPa to a final pressure of 2000 kPa. Estimate the temperature change and the entropy change of the isobutane. The specific heat of liquid isobutane at 360 K is \(2.78 J \cdot g^{−1} \cdot °C^{−1}\). Estimates of V and β may be found from Eq. (3.68).
Text Transcription:
2.78 J dot g^−1 dot °C^−1
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