?The enthalpy of a pure ideal gas depends on temperature only. Hence, \(H^{ig}\) is
Chapter 6, Problem 6.88(choose chapter or problem)
The enthalpy of a pure ideal gas depends on temperature only. Hence, \(H^{ig}\) is often said to be “independent of pressure,” and one writes \((∂ H^{ig} / ∂ P )_{T} = 0\) . Determine expressions for \((∂H^{ig} / ∂ P )_{V}\) and \((∂H^{ig} / ∂P)_{S}\) . Why are these quantities not zero?
Text Transcription:
H^ig
(∂ H^ig / ∂ P )_T = 0
(∂H^ig / ∂ P )_V
(∂H^ig / ∂P)_S
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