?Laboratory A reports the following results for equimolar values of \(G^{E}\) for liquid
Chapter 10, Problem 10.35(choose chapter or problem)
Laboratory A reports the following results for equimolar values of \(G^{E}\) for liquid mixtures of benzene(1) with 1-hexanol(2):
\(G^{E}=805 \mathrm{J} \cdot \mathrm{mol}^{-1} \text { at } T=298 \mathrm{K} \quad G^{E}=785 \mathrm{J} \cdot \mathrm{mol}^{-1} \text { at } T=323 \mathrm{K}\)
Laboratory B reports the following result for the equimolar value of \(H^{E}\) for the same system:
\(H^{E}=1060 \mathrm{J} \cdot \mathrm{mol}^{-1} \text { at } T=313 \mathrm{K}\)
Are the results from the two laboratories thermodynamically consistent with one another? Explain.
Text Transcription:
G^E
G^E = 805 J cdot mol^-1 at T=298 K G^E = 785 J cdot mol^-1 at T= 323 K
H^E
H^E = 1060 J cdot mol^-1 at T=313 K
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