?In the ammonia (NH3) molecule of Fig. 9-40, three hydrogen (H) atoms form an
Chapter 9, Problem 7(choose chapter or problem)
In the ammonia (NH3) molecule of Fig. 9-40, three hydrogen (H) atoms form an equilateral triangle, with the center of the triangle at distance \(d=9.40 \times 10^{-11} \mathrm{m}\) from each hydrogen atom. The nitrogen (N) atom is at the apex of a pyramid, with the three hydrogen atoms forming the base. The nitrogen-to-hydrogen atomic mass ratio is 13.9, and the nitrogen- to-hydrogen distance is \(L=10.14 \times 10^{-11} \mathrm{m}\). What are the (a) x and (b) y coordinates of the molecule’s center of mass?
Text Transcription:
d = 9.40 × 10^−11 m
L = 10.14 × 10^−11 m
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