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Because fluorine has seven valence electrons (\(2s^2 2p^5\)), seven covalent bonds in principle could form around the atom. Such a compound might be \(FH_7\) or \(FCl_7\). These compounds have never been prepared. Why?
Chapter 9, Problem 9.63(choose chapter or problem)
Because fluorine has seven valence electrons \(2{{s}^{2}}\ 2{{p}^{5}} \), seven covalent bonds in principle could form around the atom. Such a compound might be \(\rm{FH}_{7}\) or \(\rm{FCl}_{7}\). These compounds have never been prepared. Why?
Questions & Answers
QUESTION:
Because fluorine has seven valence electrons \(2{{s}^{2}}\ 2{{p}^{5}} \), seven covalent bonds in principle could form around the atom. Such a compound might be \(\rm{FH}_{7}\) or \(\rm{FCl}_{7}\). These compounds have never been prepared. Why?
ANSWER:Step 1 of 2
Given data:
Because fluorine has seven valence electrons \(2{{s}^{2}}\ 2{{p}^{5}} \), seven covalent bonds in principle could form around the atom. Such a compound might be \(\rm{FH}_{7}\) or \(\rm{FCl}_{7}\). These compounds have never been prepared. Why?