Using the average atomic masses given inside the front cover of this book, calculate the mass in grams of each of the following samples. a. 0.341 mole of potassium nitride b. 2.62 mmol of neon (1 mmol 5 1/1000 mol) c. 0.00449 mole of manganese(II) oxide d. \(7.18 \times 10^{5}\) moles of silicon dioxide e. 0.000121 mole of iron(III) phosphate

Chapter 9, Problem 22

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QUESTION:

Using the average atomic masses given inside the front cover of this book, calculate the mass in grams of each of the following samples.

a. 0.341 mole of potassium nitride

b. 2.62 mmol of neon (1 mmol = 1/1000 mol)

c. 0.00449 mole of manganese(II) oxide

d. \(7.18 \times 10^{5}\) moles of silicon dioxide

e. 0.000121 mole of iron(III) phosphate

Questions & Answers

QUESTION:

Using the average atomic masses given inside the front cover of this book, calculate the mass in grams of each of the following samples.

a. 0.341 mole of potassium nitride

b. 2.62 mmol of neon (1 mmol = 1/1000 mol)

c. 0.00449 mole of manganese(II) oxide

d. \(7.18 \times 10^{5}\) moles of silicon dioxide

e. 0.000121 mole of iron(III) phosphate

ANSWER:

Step 1 of 6

The moles of any element are concerned with the molar mass and the mass of the element. Hence, by using molar mass, we can convert moles to molar mass.

\(moles = \frac{{mass}}{{molar\;mass}}\)

\(mass = moles \times molar\;mass\)

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