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Monkey and Cart: Impact of Cantaloupe on Speed
Chapter 10, Problem 26(choose chapter or problem)
Questions & Answers
QUESTION: A monkey has a cart with a horizontal spring attached to it that she uses for different tricks. In one trick, the monkey sits on the vibrating cart. When the cart reaches its maximum displacement from equilibrium, the monkey picks up a 0.30-kg cantaloupe from a trainer. The mass of the monkey and the cart together is 3.0 kg. The spring constant is 660 N/m. The amplitude of horizontal vibrations is 0.24 m. Determine the ratio of the maximum speed of the monkey before and after she picks up the cantaloupe.
ANSWER:Step 1 of 4
We are given a system that is constructed of a monkey sitting on a cart with a horizontal spring attached to it.
The mass of an object picked by a monkey is \(m' = 0.30\;{\rm{kg}}\).
The mass of the cart and the monkey together equals \(m = 3.0\;{\rm{kg}}\).
The spring constant is \(k = 660\;{\rm{N/m}}\).
The amplitude of horizontal vibrations is \(A = 0.24\;{\rm{m}}\).
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Monkey and Cart: Impact of Cantaloupe on Speed
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Join us as we delve into the physics of a monkey and her cart, complete with a spring. Witness the intriguing change in maximum speed when the monkey picks up a cantaloupe. Learn how mass and vibrations affect the outcome.