Forces of 3.0 N and 4.0 N act at right angles on a block

Here consider Two forces of magnitude 3N and 4N, are applied to an object. The relative direction of the forces is unknown. The two limits for adding the forces give that the magnitude of the net force must be 1N F 7N so 5N is excluded. net Net force of these two vectors should be 5N Therefore from newton’s second law F = ma a = F/m a = 5N/2 kg a = 2.5 m/s Or 2 2 The net force is given by F (3N) + (4N) = 25N = 5 N. Then Therefore from newton’s second law F = ma a = F/m a = 5N/2 kg 2 a = 2.5 m/s