The flywheel of an engine has moment of inertia 2.50 kg · m2 about its rotation axis. What constant torque is required to bring it up to an angular speed of 400 rev/min in 8.00 s, starting from rest?

Solution to 9DQ Step 1 We need to find the constant torque that is required to bring the angular velocity of the flywheel to 400 rev/min in 8s. 2 Moment of inertia of flywheel =2.5kgm Angular speed =400 rev/min Angular speed in rad/s =41.89rad/s Time =8s Step 2 =t =41.89 x8 =335.12 rad/s2