A 2-kg particle is acted upon by the force, expressed in
Chapter 13, Problem 13.126(choose chapter or problem)
A 2-kg particle is acted upon by the force, expressed in newtons, \(\mathbf{F}=(8-6 t) \mathbf{i}+\left(4-t^{2}\right) \mathbf{j}+(4+t) \mathbf{k}\). Knowing that the velocity of the particle is \(\mathbf{v}=(150 \ \mathrm{m} / \mathrm{s}) \mathbf{i}+(100 \ \mathrm{m} / \mathrm{s}) \mathbf{j}-(250 \ \mathrm{m} / \mathrm{s}) \mathbf{k}\) at t = 0, determine (a) the time at which the velocity of the particle is parallel to the yz plane, (b) the corresponding velocity of the particle.
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