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Arrange the elements in order of increasing ionization

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 79P Chapter 9

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 79P

PROBLEM 79P

Arrange the elements in order of increasing ionization energy: Te, Pb, Cl, S, Sn.

Step-by-Step Solution:

Solution 79P

Step 1:

Ionization energy is the energy required to remove the most loosely held electron from an isolated gaseous atom

 

Variation in ionization energy down a group

Ionization energy decreases down a group. This is because the atomic size increases down a group. Hence the effective nuclear pull experienced by the outermost electron will be lesser and it will be easy to remove it.

 

Variation in ionization energy across a period

As we move from left to right in a period, ionization energy increases. This is because size of the atoms decreases as we move towards the right .Hence the effective nuclear pull experienced by the outermost electron increase and it will be difficult to remove it.

Step 2:

Pb is found in the 6th row(towards the bottom of the periodic table) and hence has the least ionization energy among the five atoms.Sn being in the 5th row of the periodic table has a higher ionization energy than Pb.Te has a higher ionization energy than Sn since it is found to the right of Sn.Similarly S has a higher ionization energy than Te(found in the same group)since it is placed at the top of the group.Cl has a higher energy than S since it is found towards the right of S in the third row of the periodic table.

Step 3 of 3

Chapter 9, Problem 79P is Solved
Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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