Solution Found!
Tangent planes Find an equation of the plane
Chapter 10, Problem 45E(choose chapter or problem)
Tangent planes Find an equation of the plane tangent to the following surfaces at the given point
\(\sin x y z=\frac{1}{2} ;\left(\pi, 1, \frac{1}{6}\right)\)
Questions & Answers
QUESTION:
Tangent planes Find an equation of the plane tangent to the following surfaces at the given point
\(\sin x y z=\frac{1}{2} ;\left(\pi, 1, \frac{1}{6}\right)\)
ANSWER:Solution 45EStep 1 of 3:In this problem we need to find an equation of the plane tangent to the surface at the given point .FORMULA: An equation of the tangent plane to the surface z = f(x , y) at the point P(is : Z - = ()) + ()) …………….(1)Here , ) denotes the partial derivative of ‘f’ with respect to x at () and ) denotes the partial derivative of ‘f’ with respect to y at () .