Solution Found!
Value of a seriesa. Find the value of the series
Chapter 11, Problem 62E(choose chapter or problem)
Values of a series
a. Find the value for the series
\(\sum_{k=1}^{\infty} \frac{3^{k}}{\left(3^{k+1}-1\right)\left(3^{k}-1\right)}\)
b. For what value of a does the series
\(\sum_{k=1}^{\infty} \frac{a^{k}}{\left(a^{k+1}-1\right)\left(a^{k}-1\right)}\)
Coverage, and in those cases, what is its value?
Questions & Answers
QUESTION:
Values of a series
a. Find the value for the series
\(\sum_{k=1}^{\infty} \frac{3^{k}}{\left(3^{k+1}-1\right)\left(3^{k}-1\right)}\)
b. For what value of a does the series
\(\sum_{k=1}^{\infty} \frac{a^{k}}{\left(a^{k+1}-1\right)\left(a^{k}-1\right)}\)
Coverage, and in those cases, what is its value?
ANSWER:SOLUTION
Step 1
We have to find the value of the series
Let us just substitute and do the partial decomposition.
Therefore
If
And therefore
Therefore we get
re substitute
Therefore
Therefore the value of