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Solved: Jogging Jake runs along a train flatcar that moves
Chapter 3, Problem 41TAR(choose chapter or problem)
Jogging Jake runs along a train flatcar that moves at the velocities shown in positions \(\mathrm{A–D}\). From greatest to least, rank Jake’s velocities relative to a stationary observer on the ground. (Call the direction to the right positive.)
Questions & Answers
QUESTION:
Jogging Jake runs along a train flatcar that moves at the velocities shown in positions \(\mathrm{A–D}\). From greatest to least, rank Jake’s velocities relative to a stationary observer on the ground. (Call the direction to the right positive.)
ANSWER:
Step 1 of 4
In part (a), according to the given sign convention the relative velocity of the jogger can be given as,
\(v_{A}=v_{f}-v_{b}\)
For \(v_{f}=8 \mathrm{~m} / \mathrm{s}\) and \(v_{b}=4 \mathrm{~m} / \mathrm{s}\),
\(\begin{aligned}
v_{A} & =8-4 \\
& =4 \mathrm{~m} / \mathrm{s}
\end{aligned}\)