The specific heat capacity of steel is 450 J/kg?°C. Show
Chapter 7, Problem 38TAS(choose chapter or problem)
The specific heat capacity of steel is \(450 \quad \mathrm{J} / \mathrm{kg} \cdot{ }^{\circ} \mathrm{C}\). Show that the amount of heat needed to raise the temperature of a 10-kg piece of steel from \(0^{\circ} \mathrm{C}\) to \(100^{\circ} \mathrm{C}\) is 450,000 J. How does this compare with the heat needed to raise the temperature of the same mass of water through the same temperature difference?
Text Transcription:
450 J / kg cdot^circ C
0^circ C
100^circ C
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